Lemma 4.2:
Let be a finite group and let be a character. Then
- .
In particular, .
Proof:
Since is finite, each has finite order . Furthermore, let such that ; then and thus . Hence, we are allowed to cancel and
- .
Lemma 4.3:
Let be a finite group and let be characters. Then the function is also a character.
Proof:
- ,
since is a field and thus free of zero divisors.
Lemma 4.4:
Let be a finite group and let be a character. Then the function is also a character.
Proof: Trivial, since as shown by the previous lemma.
The previous three lemmas (or only the first, together with a few lemmas from elementary group theory) justify the following definition.
Definition 4.5
Let be a finite group. Then the group
is called the character group of .
We need the following result from group theory:
Proof:
Since is the disjoint union of the cosets of , is the disjoint union , as and . Hence, the cardinality of equals .
Furthermore, if , then , and hence is a subgroup.