C++ Programming/Code/Standard C Library/Functions/va arg
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va_arg
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#include <cstdarg>
type va_arg( va_list argptr, type );
void va_end( va_list argptr );
void va_start( va_list argptr, last_parm );
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The va_arg() macros are used to pass a variable number of arguments to a function.
- First, you must have a call to va_start() passing a valid va_list and the name of the last argument variable before the ellipsis ("..."). This first argument can be anything; one way to use it is to have it be an integer describing the number of parameters being passed.
- Next, you call va_arg() passing the va_list and the type of the argument to be returned. The return value of va_arg() is the current parameter.
- Repeat calls to va_arg() for however many arguments you have.
- Finally, a call to va_end() passing the va_list is necessary for proper cleanup.
int sum( int num, ... ) {
int answer = 0;
va_list argptr;
va_start( argptr, num );
for( ; num > 0; num-- ) {
answer += va_arg( argptr, int );
}
va_end( argptr );
return( answer );
}
int main( void ) {
int answer = sum( 4, 4, 3, 2, 1 );
printf( "The answer is %d\n", answer );
return( 0 );
}
This code displays 10, which is 4+3+2+1.
Here is another example of variable argument function, which is a simple printing function:
void my_printf( char *format, ... ) {
va_list argptr;
va_start( argptr, format );
while( *format != '\0' ) {
// string
if( *format == 's' ) {
char* s = va_arg( argptr, char * );
printf( "Printing a string: %s\n", s );
}
// character
else if( *format == 'c' ) {
char c = (char) va_arg( argptr, int );
printf( "Printing a character: %c\n", c );
break;
}
// integer
else if( *format == 'd' ) {
int d = va_arg( argptr, int );
printf( "Printing an integer: %d\n", d );
}
*format++;
}
va_end( argptr );
}
int main( void ) {
my_printf( "sdc", "This is a string", 29, 'X' );
return( 0 );
}
This code displays the following output when run:
Printing a string: This is a string Printing an integer: 29 Printing a character: X