C++ Programming/Scope/Examples/Confusing Scope Program
Appearance
// Confusing Scope Program
#include <iostream>
using namespace std;
int i = 5; /* The first version of the variable 'i' is now in scope */
void p(){
int i = -1; /* A ''new'' variable, also called 'i' has come into existence. The 'i' declared above is now out of scope,*/
i = i + 1;
cout << i << ' '; /* so this ''local'' 'i' will print out the value 0.*/
} /* The newest variable 'i' is now out of scope. The first variable, also called 'i', is in scope again now.*/
int main(){
cout << i << ' '; /* The first variable 'i' is still in scope here so a ''5'' will be output here.*/
char ch;
int i = 6; /* A ''new'' variable, also called 'i' has come into existence. The first variable 'i' is now out of scope again,*/
i = i + 1;
p();
cout << i << endl; /* so this line will print out a ''7''.*/
return 0;
} /* End of program: all variables are, of course, now out of scope.*/