Definition: Taylor series
A function
is said to be analytic if it can be represented by the an infinite power series

The Taylor expansion or Taylor series representation of a function, then, is

sin(x) and Taylor approximations, polynomials of degree 1, 3, 5, 7, 9, 11 and 13.
Here,
is the factorial of
and
denotes the
th derivative of
at the point
. If this series converges for every
in the interval
and the sum is equal to
, then the function
is called analytic. To check whether the series converges towards
, one normally uses estimates for the remainder term of Taylor's theorem. A function is analytic if and only if a power series converges to the function; the coefficients in that power series are then necessarily the ones given in the above Taylor series formula.
If
, the series is also called a Maclaurin series.
The importance of such a power series representation is threefold. First, differentiation and integration of power series can be performed term by term and is hence particularly easy. Second, an analytic function can be uniquely extended to a holomorphic function defined on an open disk in the complex plane, which makes the whole machinery of complex analysis available. Third, the (truncated) series can be used to approximate values of the function near the point of expansion.
The function
is not analytic: the Taylor series is 0, although the function is not.
Note that there are examples of infinitely often differentiable functions
whose Taylor series converge, but are not equal to
. For instance, for the function defined piecewise by saying that
, all the derivatives are 0 at
, so the Taylor series of
is 0, and its radius of convergence is infinite, even though the function most definitely is not 0. This particular pathology does not afflict complex-valued functions of a complex variable. Notice that
does not approach 0 as
approaches 0 along the imaginary axis.
Some functions cannot be written as Taylor series because they have a singularity; in these cases, one can often still achieve a series expansion if one allows also negative powers of the variable
; see Laurent series. For example,
can be written as a Laurent series.
The Parker-Sockacki theorem is a recent advance in finding Taylor series which are solutions to differential equations. This theorem is an expansion on the Picard iteration.
Suppose we want to represent a function as an infinite power series, or in other words a polynomial with infinite terms of degree "infinity". Each of these terms are assumed to have unique coefficients, as do most finite-polynomials do. We can represent this as an infinite sum like so:

where
is the radius of convergence and
are coefficients. Next, with summation notation, we can efficiently represent this series as

which will become more useful later. As of now, we have no schematic for finding the coefficients other than finding each one in the series by hand. That method would not be particularly useful. Let us, then, try to find a pattern and a general solution for finding the coefficients. As of now, we have a simple method for finding the first coefficient. If we substitute
for
then we get

This gives us
. This is useful, but we still would like a general equation to find any coefficient in the series. We can try differentiating with respect to x the series to get

We can assume
and
are constant. This proves to be useful, because if we again substitute
for
we get

Noting that the first derivative has one constant term (
) we can find the second derivative to find
. It is

If we again substitute
for
:

Note that
's initial exponent was 2, and
's initial exponent was 1. This is slightly more enlightening, however it is still slightly ambiguous as to what is happening. Going off the previous examples, if we differentiate again we get

If we substitute
we, again, that

By now, the pattern should be becoming clearer.
looks suspiciously like
. And indeed, it is! If we carry this out
times by finding the
th derivative, we find that the multiple of the coefficient is
. So for some
, for any integer
,

Or, with some simple manipulation, more usefully,

where
and
and so on. With this, we can find any coefficient of the "infinite polynomial". Using the summation definition for our "polynomial" given earlier,

we can substitute for
to get

This is the definition of any Taylor series. But now that we have this series, how can we derive the definition for a given analytic function? We can do just as the definition specifies, and fill in all the necessary information. But we will also want to find a specific pattern, because sometimes we are left with a great many terms simplifying to 0.
First, we have to find
. Because we are now deriving our own Taylor Series, we can choose anything we want for
, but note that not all functions will work. It would be useful to use a function that we can easily find the
-th derivative for. A good example of this would be
. With
chosen, we can begin to find the derivatives. Before we begin, we should also note that
is essentially the "offset" of the function along the x-axis, because this is also essentially true for any polynomial. With that in mind, we can assume, in this particular case, that the offset is
and so
. With that in mind, "0-th" derivative or the function itself would be

If we plug that in to the definition of the first term in the series, again noting that
, we get

where
. This means that the first term of the series is 0, because anything multiplied by 0 is 0. Take note that not all Taylor series start out with a 0 term. Next, to find the next term, we need to find the first derivative of the function. Remembering that the derivative of
is
we get that

This means that our second term in the series is

Next, we need to find the third term. We repeat this process.

Because the derivative of
. We continue with

The fourth term:


Repeating this process we can get the sequence

which simplifies to

Because we are ultimately dealing with a series, the zero terms can be ignored, giving use the new sequence

There is a pattern here, however it may be easier to see if we take the numerator and the denominator separately. The numerator:


And for the
part of the terms, we have the sequence

By this point, at least for the denominator and the
part, the pattern should be obvious. It is, for the denominator

The
term:

Finally, the numerator may not be as obvious, but it follows this pattern:

With all of these things discovered, we can put them together to find the rule for the
th term of the sequence:

And so our Taylor (Maclaurin) series for
is

Several important Taylor series expansions follow. All these expansions are also valid for complex arguments
.
Exponential function and natural logarithm:


Geometric series:

Binomial series:

Trigonometric functions:






Hyperbolic functions:





Lambert's W function:

The numbers
appearing in the expansions of
and
are the Bernoulli numbers. The
in the binomial expansion are the binomial coefficients. The
in the expansion of
are Euler numbers.
The Taylor series may be generalized to functions of more than one variable with

The Taylor series is named for mathematician Brook Taylor, who first published the power series formula in 1715.
Several methods exist for the calculation of Taylor series of a large number of functions. One can attempt to use the Taylor series as-is and generalize the form of the coefficients, or one can use manipulations such as substitution, multiplication or division, addition or subtraction of standard Taylor series (such as those above) to construct the Taylor series of a function, by virtue of Taylor series being power series. In some cases, one can also derive the Taylor series by repeatedly applying integration by parts. The use of computer algebra systems to calculate Taylor series is common, since it eliminates tedious substitution and manipulation.
Consider the function

for which we want a Taylor series at 0.
We have for the natural logarithm

and for the cosine function

We can simply substitute the second series into the first. Doing so gives

Expanding by using multinomial coefficients gives the required Taylor series. Note that cosine and therefore
are even functions, meaning that
, hence the coefficients of the odd powers
,
,
,
and so on have to be zero and don't need to be calculated.
The first few terms of the series are

The general coefficient can be represented using Faà di Bruno's formula. However, this representation does not seem to be particularly illuminating and is therefore omitted here.
Suppose we want the Taylor series at 0 of the function

We have for the exponential function

and, as in the first example,

Assume the power series is

Then multiplication with the denominator and substitution of the series of the cosine yields
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Collecting the terms up to fourth order yields

Comparing coefficients with the above series of the exponential function yields the desired Taylor series
