In converting
to
the underlying vector doesn't
change.
Thus,
this translation is accomplished by the identity map on the space,
described so that
the domain space vectors are represented with respect to and
the codomain space vectors are represented with respect to .
(The diagram is
vertical to fit with the ones in the next subsection.)
- Proof
For the first sentence, for each , as matrix-vector multiplication represents a map application, . For the second sentence, with respect to the matrix represents some linear map, whose action is , and is therefore the identity map.
- Example 1.3
With these bases for ,
because
the change of basis matrix is this.
We can see this matrix at work by finding the two representations of
and checking that the conversion goes as expected.
We finish this subsection by recognizing that the change of basis matrices
are familiar.
- Lemma 1.4
A matrix changes bases if and only if it is nonsingular.
- Proof
For one direction, if left-multiplication by a matrix changes bases then
the matrix represents an invertible function,
simply because the function is inverted by changing the bases back.
Such a matrix is itself invertible, and so nonsingular.
To finish, we will show that any nonsingular matrix
performs a change of basis operation from any given starting basis
to some ending basis.
Because the matrix is nonsingular, it will Gauss-Jordan reduce to the
identity, so there are elementatry reduction matrices such that
.
Elementary matrices are invertible and their inverses are also elementary,
so multiplying from the left first
by , then by , etc., gives
as a product of elementary matrices
.
Thus, we will be done if we show that elementary matrices
change a given basis to another basis, for then
changes to some other basis , and
changes to some , ..., and
the net effect is that changes to .
We will prove this about elementary matrices by covering the three types as
separate cases.
Applying a row-multiplication matrix
changes a representation with respect to
to one with respect to
in this way.
-
Similarly, left-multiplication by a row-swap matrix
changes a representation with respect to the basis
into one with respect to the basis
in this way.
-
And, a representation with respect to
changes via left-multiplication by a row-combination matrix
into a representation with respect to
-
(the definition of reduction matrices specifies that and and so this last one is a basis).
- Corollary 1.5
A matrix is nonsingular if and only if it represents the identity map with respect to some pair of bases.
In the next subsection we will
see how to translate among representations of
maps, that is, how to change
to .
The above corollary is a special case of this, where the domain and range are
the same space, and where the map is the identity map.
- This exercise is recommended for all readers.
- This exercise is recommended for all readers.
- Problem 2
Find the change of basis matrix for .
- ,
- ,
- ,
- ,
- Problem 3
For the bases in Problem 2,
find the change of basis matrix in the other direction, from to .
- This exercise is recommended for all readers.
- Problem 4
Find the change of basis matrix for each .
-
-
-
- This exercise is recommended for all readers.
- Problem 6
Find bases such that this matrix represents the identity map
with respect to those bases.
- Problem 7
Conside the vector space of real-valued functions with basis
.
Show that
is also a basis for this space.
Find the change of basis matrix in each direction.
- Problem 8
Where does this matrix
send the standard basis for ?
Any other bases?
Hint.
Consider the inverse.
- This exercise is recommended for all readers.
- Problem 9
What is the change of basis matrix with respect to ?
- Problem 10
Prove that a matrix changes bases if and only if it is invertible.
- This exercise is recommended for all readers.
- This exercise is recommended for all readers.
- Problem 14
Let be vector spaces, and let be bases for
and be bases for .
Where is linear, find a formula relating
to .
- This exercise is recommended for all readers.
- This exercise is recommended for all readers.
Solutions